nikan
Posts: 2
Joined: Wed Nov 22, 2017 1:02 am

### Calculating base resistor - PN2222

So glad to join Sciencebuddies where has many professional members and rich professional knowledge. And for my question I'm not looking particularly for a quick reply, just one that may concretely address these low-level questions.

I've been continuing to play with small circuits and Im trying to sort out how to calculate the resistor for the base of this transistor. The transistor is a pn2222 (http://www.kynix.com/uploadfiles/pdf8798/PN2222.pdf). Its my understanding that the resistor for the LED should be calculated much in the same way I would without the transistor. In this case, I know the LED drops 2.48 volts and draws 46mA. So my resistor for the LED is 54 ohms and I used a 47 ohm resistor.

I've tried many different formulas to try and figure out what the base resistor should be used and I can't seem to get it right. From my reading this is important because too much current could open the transistor too far and block the current coming from the collector through to the emitter.

I tried using this formula...

R = Voltage x hfe / LED current R = 4.3 x 35 / .05

That gave me 3010 and when I use a 3k resistor I only get about 30 milliamps of current to the LED. Shouldn't I get the full 46 as I see when the LED and resistor are plugged directly into the power source?

Also - in the above circuit I subtracted .7 volts from voltage since that just seems to be what everyone was doing. In reality, when I check the voltage drop from collector to emitter and base to emitter I see .8v and .6 v respectively. Shouldn't this be factored in? What about the voltage drop of the LED?

Im lost.

Edit: Im really new to this space and still learning so your comments will be very helpful. I've moved the LED and it's series resistor to the collector leg of the transistor. The more I think about this, the more I see that Im dealing with two parallel circuits on the same power supply as I've drawn out.

If this is the case, I can see how having the LED as part of circuit 2 would impact the power required to drive the transistor. Having it in it's own leg on the collector means that I can deal with it separately. I've also measured the voltage drop from base to emitter and verified that it's right around .7 volts which seems to match the value everyone else has been using for transistor voltage drop. At this point Im just trying to sort out the math for driving the transistor to saturation. What Im not confused about is which spec on the sheet I should be looking at in order to figure this out. For instance, the spec sheet lists saturation values for for collector-base as well as base-emitter. Im getting the feeling that Im getting too far ahead of myself here. Just by moving to this new configuration and having a 3k ohm resistor on the base it seems to work, Im just trying to prove out why that works now.
Thanks!

norman40
Expert
Posts: 702
Joined: Mon Jul 14, 2014 1:49 pm
Occupation: retired chemist

### Re: Calculating base resistor - PN2222

Hi nikan,

Is your question related to a science fair project? This forum is intended for students, parents, and teachers working on K-12 science projects. If you are looking for help with homework or general science discussions there are other sites that should be able to answer your question.

A. Norman

nikan
Posts: 2
Joined: Wed Nov 22, 2017 1:02 am

### Re: Calculating base resistor - PN2222

norman40 wrote:Hi nikan,

Is your question related to a science fair project? This forum is intended for students, parents, and teachers working on K-12 science projects. If you are looking for help with homework or general science discussions there are other sites that should be able to answer your question.

A. Norman

Thank you for your reminding, Norman!