According to the datasheet of DS18B20temperature sensor, it is clear that the sensor is digital so the output is in digital form.
The resolution of the temperature sensor is 9, 10, 11, or 12 bits, corresponding to increments of 0.5°C, 0.25°C, 0.125°C, and 0.0625°C, respectively, and by default it is 12-bits. Which means, for 12-bits, a change of 0.0625°C in temperature causes an increment of 1-bit.
But there is no information given on how much change in voltage will result from a change in Temperature (i.e. scale factor). For example, there is an analog temperature sensor in which a change of 10mV in the output voltage is equal to a change of 1°C of temperature.
Is there any way to calculate the scale factor of the digital temperature sensor like the way we do for analog?
ADC in Digital Temperature Sensor DS18B20
Moderators: kgudger, bfinio, MadelineB, Moderators
-
- Posts: 1
- Joined: Thu Jul 27, 2017 2:22 am
- Occupation: Teacher
-
- Moderator
- Posts: 908
- Joined: Fri Jun 20, 2014 4:42 pm
- Occupation: Biostatistician/Data Scientist
- Project Question: Interested in volunteering as an expert
- Project Due Date: n/a
- Project Status: Not applicable
Re: ADC in Digital Temperature Sensor DS18B20
Hello and thank you for your patience in waiting for a response!
The "Ask the Expert" forum is for students (and their teachers) in grades K-12 who are doing science experiments.
It would help us to help you if you could describe the science project including the hypotheses and experimental design that your question relates to. If your question does not relate to a science project, then there are other forums on the internet where your question would be more appropriate.
Thank you!
The "Ask the Expert" forum is for students (and their teachers) in grades K-12 who are doing science experiments.
It would help us to help you if you could describe the science project including the hypotheses and experimental design that your question relates to. If your question does not relate to a science project, then there are other forums on the internet where your question would be more appropriate.
Thank you!