Science Buddies: "Ask an Expert"

Sir, As we know the earth rotates very fast with the speed of approx 1680km/h and on the other hand ,the passenger Airbus goes with the avg. speed of 850km/h(nearly half of earth) which is less than the rotation of earth. So, how the airbus is able to reach its direction when flying in the direction of earth(specially on the route nearer to the equator)?. Does it fly in opposite direction of the earth to reach its destination?OR the engine generate sufficient power to go with the speed of (1680+850)km/h.

It is obvious that at the time when airplane takes off it is in contact with earth and its relative speed is positive w.r.t the rotation of Earth.When it losses its contact with earth, due to inertia its relative speed is still positive till sometime( Because Probably the friction due to air would decrease the speed gained due to inertia ), And now the plane is left all alone with its own power, And again the Question withstands that how does crafts reach their destination?
Hoping an understandable reply......
Thank You.......

In higher level physics, there are concepts of a "Reference Frame" and "Relativity". You should research these terms.

A plane "at rest" on the tarmac of an airport is ONLY "at rest" with respect to the reference frame (or coordinate system). If the reference frame chosen is the axis of rotation of the earth, the equator and the prime meridian, then the reference frame is rotating at aproximately 360 degrees in 24 hours. Note: This latitude, longitude reference frame plus time is what world travelers have been using for centuries as their coordinate system for measuring their position. Aditionally, the reference frame origin is moving on an eliptical orbit around the sun. The sun is moving with respect to the galaxy, The galaxy is moving with respect to the universe. If one wanted to figure out the movement of the plane/tarmac with respect to the center of the universe, that would be a horribly complex if not impossible problem.

Engineers and physicists always try to choose a reference frame to minimize their calculation efforts.

On a hypothetically windless day, the atmosphere is also stationary (not moving) with respect to this same reference frame. In reality, there is no such thing as a windless day in the entire earth's atmosphere. The wind maybe calm at your location on the earth's surface, but air is definitely moving elsewhere. It may even be moving significantly at several thousand feet above your location.

For a plane to obtain lift, it has to be traveling at some minimum speed (look up stall speed of airbus) with respect to the wind. The engines only need to provide enough force (thrust) to obtain an "air speed" (the relative measurement is now with respect to a different reference frame) that is sufficiently higher than the stall speed to provide a safety factor and climb rate. Because the "at rest" plane was already moving with the earth's reference frame, no additional force is required. The only force required is that to provide lift and to overcome the difference in the wind and earth's reference frame relative movements.

Planes try to take off and land into the wind so that their ground speed is added to the wind speed with respect to the ground to maximize their air speed at takeoff and landing and increase safety margins.

Thanks Criag,
All I understand is that the plane is moving in reference frame of earth and even at the height( When contact with earth is lost ) The plane is moving wrt this frame of reference.
In Simple words can we say that "earths atmosphere is also in continuous motion due to rotation of earth and the plane is being carried with the atmosphere at speed of approx 1680km/h and use its own power to go with relative speed (avg)850km/h"?
Please tell me that how far i am right or wrong with my statement...

I think you understand the basics if you ignore wind (the movement of the atmosphere wrt the earth's reference frame).
Wind is a complicating factor because once aloft, the airplane's engines are working relative to the wind.