Testing for Sugar in food
Posted: Mon Dec 12, 2016 6:03 pm
I am working on Uncovering Hidden Sugar in Food. As I started answering the wrap up questions for this project, I noticed that one of the formulas was using the equation 10% x 1%= 10%, Analyzing Your Results
Look at the graph you made in the "Testing the Foods for Glucose Concentration Before and After Adding Invertase" section (step 12). Do the glucose readings you took before adding the invertase match what you would expect for these foods?
Which foods had the most glucose before adding the invertase? Which had the least? Did any have no glucose?
Using the data you collected, you can determine the sucrose concentration in each of the foods you tested.
Look at the graph you made in the "Testing Invertase Activity" section. At the linear time point, what was the glucose concentration? If you multiply the glucose concentration at the linear time point by the original sucrose concentration (10%), this will tell you what percentage of the total sucrose was converted to glucose at this time point. We will call this value "Percentage of sucrose converted." You can see this equation written out in Equation 1.
For example, if at the linear time point the 10% sucrose solution had a reading of 1% glucose, then this means that 10% of the total sucrose (10% multiplied by 1%) had been converted to glucose.
Originalsucroseconcentration×Glucoseconcentrationatlineartimepoint=Percentageofsucroseconverted
When I multiply 10% x 1% I do not get 10%. I get .001 which is .1%
Is the formula being used wrong?? Please advise as soon as possible!!!
Another question: If my percentage of original sucrose converted is 7.5% and I'm testing for the original sucrose concentration of food, my figures for original sucrose concentration are coming up much lower than my glucose at linear time point figures. For instance: Green Beans have an original sucrose concentration of 1.5% as opposed to honeycrisp apples which have an original sucrose concentration of .375%
Green Beans equation: 7.5 divided by 5(glucose concentration at linear time point) = 1.5 (original sucrose concentration)
Honeycrisp apples: 7.5 divided by 20(glucose concentration at linear time point) = .375 (original sucrose concentration)
I would of thought that the original sucrose concentration of honeycrisp apples would be higher than green beans. Am I interpreting something incorrectly??
Thank you for your help.
Note from the moderator: I combined your two questions into one post, so the experts who help you can see both questions - the better to help you!
Look at the graph you made in the "Testing the Foods for Glucose Concentration Before and After Adding Invertase" section (step 12). Do the glucose readings you took before adding the invertase match what you would expect for these foods?
Which foods had the most glucose before adding the invertase? Which had the least? Did any have no glucose?
Using the data you collected, you can determine the sucrose concentration in each of the foods you tested.
Look at the graph you made in the "Testing Invertase Activity" section. At the linear time point, what was the glucose concentration? If you multiply the glucose concentration at the linear time point by the original sucrose concentration (10%), this will tell you what percentage of the total sucrose was converted to glucose at this time point. We will call this value "Percentage of sucrose converted." You can see this equation written out in Equation 1.
For example, if at the linear time point the 10% sucrose solution had a reading of 1% glucose, then this means that 10% of the total sucrose (10% multiplied by 1%) had been converted to glucose.
Originalsucroseconcentration×Glucoseconcentrationatlineartimepoint=Percentageofsucroseconverted
When I multiply 10% x 1% I do not get 10%. I get .001 which is .1%
Is the formula being used wrong?? Please advise as soon as possible!!!
Another question: If my percentage of original sucrose converted is 7.5% and I'm testing for the original sucrose concentration of food, my figures for original sucrose concentration are coming up much lower than my glucose at linear time point figures. For instance: Green Beans have an original sucrose concentration of 1.5% as opposed to honeycrisp apples which have an original sucrose concentration of .375%
Green Beans equation: 7.5 divided by 5(glucose concentration at linear time point) = 1.5 (original sucrose concentration)
Honeycrisp apples: 7.5 divided by 20(glucose concentration at linear time point) = .375 (original sucrose concentration)
I would of thought that the original sucrose concentration of honeycrisp apples would be higher than green beans. Am I interpreting something incorrectly??
Thank you for your help.
Note from the moderator: I combined your two questions into one post, so the experts who help you can see both questions - the better to help you!