Calculating Efficiency of an Electrochemical cell
Posted: Thu Jan 16, 2020 8:59 pm
I did the water to fuel to water project
https://www.sciencebuddies.org/science- ... /fuel-cell
but all of the voltages that I got from the cell were less than 1.23 volts. According to the website, this would be over 100% efficiency, which is not possible.
After the experiment, I connected the multimeter probes to either side of the 10K Ohm resistor, to find out how much voltage it drops. I found that it drops 18.64 volts from four 9V batteries whose sum of volts given was 36.1V. Using Ohm's law, the current was 18.64/10000 = 1.864 mA.
How did the creators of the project get 1.23 V as the ideal voltage? How is the ideal voltage found?
Thank you.
https://www.sciencebuddies.org/science- ... /fuel-cell
but all of the voltages that I got from the cell were less than 1.23 volts. According to the website, this would be over 100% efficiency, which is not possible.
After the experiment, I connected the multimeter probes to either side of the 10K Ohm resistor, to find out how much voltage it drops. I found that it drops 18.64 volts from four 9V batteries whose sum of volts given was 36.1V. Using Ohm's law, the current was 18.64/10000 = 1.864 mA.
How did the creators of the project get 1.23 V as the ideal voltage? How is the ideal voltage found?
Thank you.