I guess I’ll start with what MFagan said as this is my area of expertise, computers, I guess even 5 years old, once only need 120w to run. A computer runs off several voltages including 12v, 5v, and 3.3v. Now that 200w is divided between those voltages but as an example lets say that the 12v part used all that wattage 120w / 12v = 10A. Due to that wattage being also shared with the other voltages 10A is over estimating it. It would be more likely around 5A. With today’s computers now being far superior, not only on the data processing side but also on the video rendering side, computers draw way more amperage then ever before. One way to fix the problem was to up the wattage and to create two or more 12 rails, this meaning that each rail had its own independent amperage that it could put out and was not shared with the other rails. This also enabled manufactures to still be within special standards. This was a good idea but many extreme gamers, and computer overclockers found that they needed more amperage on certain rails, so some companies decided to create power supplies that went back to the original single 12v rail design with a major amperage and wattage boost.
It just so happens I brought one of these top of the line power supply’s a few weeks ago, have a look at this picture
Getting back to Craig Bridge, I do see that the receiver has a small battery on it but I also notice next to that there are two capacitors which are sitting next to a set of connectors, labeled + and - which I thought were used to power the device and the battery was like a backup power supply. Not all of these devices I found on eBay have batters on the receiver.
Each relay has three connectors, I believe they are normally referred to as the following, normally open, normally closed and common, is that right?
I only want to power a few computer case fans, neon’s and LED’s, all of which are currently being powered by the power supply. I guess I should say they are all 12VDC and require very low amperage none above 1A
Is it possible to have too much amperage if it's not been drawn by a device?
Thanks to all that have replied, much appreciated