For others' reference, the project:
https://www.sciencebuddies.org/science- ... p022.shtml
A few questions that you still haven't answered...
-- What device did you use to measure the force that you pulled with? How was it connected to the objects?
-- When you predicted which objects would experience the greatest drag force, what was your reasoning?
Additionally...
-- Are you sure that you were always walking at the same pace? For example, did you time yourself over a certain distance with a stopwatch?
-- It's great that you repeated each measurement 10 times. Were the 10 measurements for a given object fairly similar, or did they vary a lot? (This is a good indication of the precision of your measurement technique.)
-- Have you seen the drag equation before? If not, what was your understanding of drag when you formulated with your hypothesis?
-- Which sides of the objects were pointing forward? (cap end or bottom of bottle, bottom or top of vase, etc)
Basically, the drag equation says that the drag force F is proportional to several quantities. One of them is the density of fluid, which you kept constant by always using water. Another is the square of the velocity -- if you were able to walk at the same speed every time, then this was also constant.
F is also proportional to an area A, which it's reasonable to approximate as the cross-sectional area of the object -- the area that's perpendicular to the direction of motion. For example, if you had a brick that was 4 inches by 5 inches by 8 inches, and you dragged it with the smallest side facing forward, then A would be 4 in * 5 in = 20 square inches. The area is important because a larger area means that more water has to be displaced as the object moves.
The last variable to which F is proportional is the drag coefficient C. This depends on the geometry, or shape, of the object. Rather than the shape of the cross-sectional area, it's the shape of the side profile that's important. Seriously, look at the shapes in the diagram in the upper right here -- the objects are moving in the direction of the arrows:
http://en.wikipedia.org/wiki/Drag_coefficient. The basic idea is that a curved or pointy surface deflects the fluid gradually, so it doesn't hit the moving object in a head-on collision and doesn't push as hard against it. The drag coefficient isn't something you can calculate -- it's usually measured experimentally.
When you design an experiment, it's best to have one independent variable (the thing you change intentionally) and one dependent variable (the quantity you measure -- here, the drag force). Everything else should be kept constant, or you won't know whether your IV caused changes in the DV or something else did. The problem with your setup might be that you have two important variables that are changing: cross-sectional area and drag coefficient. Comparing just the bottle and the brick, it's reasonable to predict that the cap end of the bottle would have a lower drag coefficient than any side of the brick, because flat is pretty much the worst surface, and the curved/pointy top of the bottle is much more similar to the 'streamlined body' shape. However, if you used a 2-liter bottle, it's likely that the bottle's cross-sectional area is somewhat larger than the brick's. Depending on the magnitudes of the differences between the areas and the drag coefficients (and the accuracy of your measurements), this could explain how you ended up with a larger drag coefficient for the bottle.
Ideally, the experiment would have been designed so that either (a) all objects had the same area, or (b) all objects had the same drag coefficient. (b) is tricky unless you use a simple geometry like a flat surface -- bricks of different sizes would work. (a) could be accomplished by something like measuring the two different ends of a bottle, or comparing a plate and a ball of the same diameter.
Assuming that you don't have time to make more measurements, here's an idea. So, you have the equation F = constant * A * C. You've measured F, and you can also measure A. If you want to "get rid of" A to test whether C corresponds to the object's geometries in the way you'd expect, you can divide both sides of the equation by A to get the drag force per unit surface area (might want to measure area in metric units since you used Newtons): F/A = constant * C.
My standard warning about Wikipedia (since I've linked there) is that it's a great first stop for looking up new terminology and finding related concepts, but it's not a primary source, and most teachers probably don't want you to cite it (for information -- of course you have to cite it if you borrow an image, etc). I suggest plugging terms like 'drag force', or anything else you don't understand, into Google or another search engine to find sources that make sense to you. You should have done some background reading before starting your experiment, so this should follow as an extension to that information.
Amanda