Absorption of Radiant Energy by Different Colors- equation 5
Moderators: AmyCowen, kgudger, bfinio, MadelineB, Moderators
-
deleted-333382
- Posts: 1
- Joined: Thu Jan 07, 2016 1:22 pm
- Occupation: Parent
Absorption of Radiant Energy by Different Colors- equation 5
Can anyone help this math challenged mama figure out how, in converting joules to eV, the exponent came out to positive 22?
-
norman40
- Former Expert
- Posts: 1022
- Joined: Mon Jul 14, 2014 1:49 pm
- Occupation: retired chemist
- Project Question: Volunteer
- Project Due Date: n/a
- Project Status: Not applicable
Re: Absorption of Radiant Energy by Different Colors- equation 5
Hi Susie50,
I’m assuming that you’re working on the project described here:
https://www.sciencebuddies.org/science- ... ml#summary
Equation 5 is a conversion from energy to the rate of photon emission. The large exponent in the final result (22) comes from division by numbers with very small exponents. Take a look at the second term on the left hand side of the equation. This division of 1 by 1.6E-19 gives 6.25E18. The division in third term (1/0.000124) gives 8.06E3. Multiplication of these two results gives 5.04E22.
I hope this helps. Please ask again if you have more questions.
A. Norman
I’m assuming that you’re working on the project described here:
https://www.sciencebuddies.org/science- ... ml#summary
Equation 5 is a conversion from energy to the rate of photon emission. The large exponent in the final result (22) comes from division by numbers with very small exponents. Take a look at the second term on the left hand side of the equation. This division of 1 by 1.6E-19 gives 6.25E18. The division in third term (1/0.000124) gives 8.06E3. Multiplication of these two results gives 5.04E22.
I hope this helps. Please ask again if you have more questions.
A. Norman

