Ski lift: pulley system
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deleted-422692
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Ski lift: pulley system
If there are two ski lifts equal in length, weight, height, etc. with the same amount of weight on each side of the cable, with one at a 45 degree angle and the other at a flat 180 degrees will it take the same amount of power to opperate them at the same speed?
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LeungWilley
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Re: Ski lift: pulley system
Hi Jacknoll,
I am guessing you are working on this experiment?
https://www.sciencebuddies.org/science- ... p100.shtml
In order to answer your question, we have to look at the equations for Power. (Power = Force (dot) (Velocity). These are vectors quantities so you can only take credit for the power that's applied in the same direction of the velocity. When the force is applied at an angle, you will need to take that into account, i.e. cosine of the angle.
I hope that make sense. Please let us know if you have any questions or if there's anything else we can help with.
Good Luck!
Willey
I am guessing you are working on this experiment?
https://www.sciencebuddies.org/science- ... p100.shtml
In order to answer your question, we have to look at the equations for Power. (Power = Force (dot) (Velocity). These are vectors quantities so you can only take credit for the power that's applied in the same direction of the velocity. When the force is applied at an angle, you will need to take that into account, i.e. cosine of the angle.
I hope that make sense. Please let us know if you have any questions or if there's anything else we can help with.
Good Luck!
Willey
-
deleted-422692
- Posts: 2
- Joined: Thu Dec 29, 2016 12:11 pm
- Occupation: Student
Re: Ski lift: pulley system
Hi i just wanna know if it would take more power or the sameLeungWilley wrote:Hi Jacknoll,
I am guessing you are working on this experiment?
https://www.sciencebuddies.org/science- ... p100.shtml
In order to answer your question, we have to look at the equations for Power. (Power = Force (dot) (Velocity). These are vectors quantities so you can only take credit for the power that's applied in the same direction of the velocity. When the force is applied at an angle, you will need to take that into account, i.e. cosine of the angle.
I hope that make sense. Please let us know if you have any questions or if there's anything else we can help with.
Good Luck!
Willey

