Help! Measuring Surface Tension

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https://www.sciencebuddies.org/science- ... #procedure
I have constructed the contraption and am unsure if I correctly calculated the surface tension of water. My spoon dropper has 15 drops in 1 mL, so that means that one drop is equal to .06666667. It took 10 drops of water for the needle to lift off of the surface of the water. Therefore, it is .66666667 as the mass. I took that number and multiplied it by 9.81×10-3. It came up to.00654. I plugged it into F=2sD along with the length of the needle which is 4.5. (.00654=2 x S x 4.5) I then rearranged it and divided .00654 by 9 and resulted in .00072667. Is this right or am I completely wrong?

[norman40]

Hi DiligentWorker,

Yes, you made the calculation correctly. Well done!

I hope this helps. Please post again if you have more questions.

A. Norman

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