track spacing
Moderators: kgudger, bfinio, MadelineB, Moderators
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kujan
- Posts: 16
- Joined: Thu Oct 19, 2006 10:06 am
track spacing
Please help me derive the formula for track spacing...d(sin θm - sin θi ) = mλ...i need it urgently as my project is due next week....Thank you...
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johnsteele
- Former Expert
- Posts: 18
- Joined: Tue Oct 03, 2006 1:41 pm
I'm not sure for what you are asking, but this might help.
https://www.sciencebuddies.org/mentorin ... p011.shtml
https://www.sciencebuddies.org/mentorin ... p011.shtml
john Steele, Enterprise Architect
Discovery consists of seeing what everybody has seen and thinking what nobody has thought.
Discovery consists of seeing what everybody has seen and thinking what nobody has thought.
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ghariman
- Former Expert
- Posts: 84
- Joined: Tue Oct 17, 2006 8:48 am
Hi Kujan,
The equation that you are as asking of:
d(sin θm - sin θi ) = mλ
is called the "Grating Equation".
Below is a website that I found that has the derivation of the equation:
http://scienceworld.wolfram.com/physics ... ating.html
Here is a very good explanation of the grating equation with many pictures. In particular look at figures 1, 2 and 4:
http://www.lot-oriel.com/site/site_down ... s_deen.pdf
Hope this helps. When reading the derivation make sure to understand each step of it and not just use it blindly.
The equation that you are as asking of:
d(sin θm - sin θi ) = mλ
is called the "Grating Equation".
Below is a website that I found that has the derivation of the equation:
http://scienceworld.wolfram.com/physics ... ating.html
Here is a very good explanation of the grating equation with many pictures. In particular look at figures 1, 2 and 4:
http://www.lot-oriel.com/site/site_down ... s_deen.pdf
Hope this helps. When reading the derivation make sure to understand each step of it and not just use it blindly.
"Genius is one percent inspiration and ninety nine percent perspiration".
- Thomas A Edison
George H
Volunteer Mentor for the Ask an Expert Forum located in California
- Thomas A Edison
George H
Volunteer Mentor for the Ask an Expert Forum located in California
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kujan
- Posts: 16
- Joined: Thu Oct 19, 2006 10:06 am
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ghariman
- Former Expert
- Posts: 84
- Joined: Tue Oct 17, 2006 8:48 am
Hi Kujan,kujan wrote:Thanks a billion George...this is very useful information...dont know wat i would have done otherwise...thanks again
KUJAN
p.s. I am an ISC student (12th grade) from India. This experiment is part of my internal assessment for my board exam. So i owe u big time...
All the best for your project then.
"Genius is one percent inspiration and ninety nine percent perspiration".
- Thomas A Edison
George H
Volunteer Mentor for the Ask an Expert Forum located in California
- Thomas A Edison
George H
Volunteer Mentor for the Ask an Expert Forum located in California
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Louise
- Former Expert
- Posts: 921
- Joined: Mon Jan 16, 2006 2:17 pm
These derivations just use simple geometry. Look closely at the figures, and the equations, and you should see how these are derived. What does each side of the equation #4 look like? (What formula?) How does that relate to the diagram of a triangle?kujan wrote:Mr. George,
i went through the links carefully as you asked me to. I do not understand how the 4th equation is obtained...could you please explain it to me...Thanks
Louise
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Louise
- Former Expert
- Posts: 921
- Joined: Mon Jan 16, 2006 2:17 pm
Well, looking at the page, they say you need to solve the 4 equations for the 4 unknowns. So the first 4 equations are the obvious geometrical constraints that you get by looking at the pictures.kujan wrote:I got #4...Thanks...but what about the other 2....how do you explain that...
(Obviously, if you look at the picture, you would get exactly what you proposes d1 and a1 should be related by the angle of the small triangle.)
So, you need to solve for d1 and d2 in terms of a (not a1 or a2) using the 4 equations above.
Louise

