track spacing

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kujan
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Joined: Thu Oct 19, 2006 10:06 am

track spacing

Post by kujan »

Please help me derive the formula for track spacing...d(sin θm - sin θi ) = mλ...i need it urgently as my project is due next week....Thank you...
johnsteele
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Post by johnsteele »

I'm not sure for what you are asking, but this might help.

https://www.sciencebuddies.org/mentorin ... p011.shtml
john Steele, Enterprise Architect
Discovery consists of seeing what everybody has seen and thinking what nobody has thought.
kujan
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Joined: Thu Oct 19, 2006 10:06 am

Post by kujan »

I already have that link...the formula used in the experiment (d(sin θm - sin θi ) = mλ)...i want to know how its derived...Thank you
johnsteele
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Post by johnsteele »

You might what to look at derivations of Bragg's law.
john Steele, Enterprise Architect
Discovery consists of seeing what everybody has seen and thinking what nobody has thought.
kujan
Posts: 16
Joined: Thu Oct 19, 2006 10:06 am

Post by kujan »

could you please send me a link...or type out the derivation...it would be really helpful....
ghariman
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Joined: Tue Oct 17, 2006 8:48 am

Post by ghariman »

Hi Kujan,

The equation that you are as asking of:
d(sin θm - sin θi ) = mλ
is called the "Grating Equation".

Below is a website that I found that has the derivation of the equation:
http://scienceworld.wolfram.com/physics ... ating.html

Here is a very good explanation of the grating equation with many pictures. In particular look at figures 1, 2 and 4:
http://www.lot-oriel.com/site/site_down ... s_deen.pdf

Hope this helps. When reading the derivation make sure to understand each step of it and not just use it blindly.
"Genius is one percent inspiration and ninety nine percent perspiration".
- Thomas A Edison

George H
Volunteer Mentor for the Ask an Expert Forum located in California
kujan
Posts: 16
Joined: Thu Oct 19, 2006 10:06 am

Post by kujan »

Thanks a billion George...this is very useful information...dont know wat i would have done otherwise...thanks again

KUJAN

p.s. I am an ISC student (12th grade) from India. This experiment is part of my internal assessment for my board exam. So i owe u big time...
ghariman
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Joined: Tue Oct 17, 2006 8:48 am

Post by ghariman »

kujan wrote:Thanks a billion George...this is very useful information...dont know wat i would have done otherwise...thanks again

KUJAN

p.s. I am an ISC student (12th grade) from India. This experiment is part of my internal assessment for my board exam. So i owe u big time...
Hi Kujan,

All the best for your project then.
"Genius is one percent inspiration and ninety nine percent perspiration".
- Thomas A Edison

George H
Volunteer Mentor for the Ask an Expert Forum located in California
kujan
Posts: 16
Joined: Thu Oct 19, 2006 10:06 am

Post by kujan »

Mr. George,

i went through the links carefully as you asked me to. I do not understand how the 4th equation is obtained...could you please explain it to me...Thanks
kujan
Posts: 16
Joined: Thu Oct 19, 2006 10:06 am

Post by kujan »

also...the 6th and the 7th equations...shouldnt it be a1 and a2 respectively?
Louise
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Post by Louise »

kujan wrote:Mr. George,

i went through the links carefully as you asked me to. I do not understand how the 4th equation is obtained...could you please explain it to me...Thanks
These derivations just use simple geometry. Look closely at the figures, and the equations, and you should see how these are derived. What does each side of the equation #4 look like? (What formula?) How does that relate to the diagram of a triangle?

Louise
kujan
Posts: 16
Joined: Thu Oct 19, 2006 10:06 am

Post by kujan »

I got #4...Thanks...but what about the other 2....how do you explain that...
Louise
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Joined: Mon Jan 16, 2006 2:17 pm

Post by Louise »

kujan wrote:I got #4...Thanks...but what about the other 2....how do you explain that...
Well, looking at the page, they say you need to solve the 4 equations for the 4 unknowns. So the first 4 equations are the obvious geometrical constraints that you get by looking at the pictures.

(Obviously, if you look at the picture, you would get exactly what you proposes d1 and a1 should be related by the angle of the small triangle.)


So, you need to solve for d1 and d2 in terms of a (not a1 or a2) using the 4 equations above.


Louise
kujan
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Joined: Thu Oct 19, 2006 10:06 am

Post by kujan »

excellent...now its crystal clear....thanks a lot...Louise

KUJAN
Louise
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Joined: Mon Jan 16, 2006 2:17 pm

Post by Louise »

kujan wrote:excellent...now its crystal clear....thanks a lot...Louise

KUJAN
Glad it is clear. Good luck with the math!

Louise
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