Quinn 123 wrote:I have a food scale but I think it would be worthless as it only measures up to 16 oz. (for diet purposes).
It would probably be easier to use measuring cups and then use the scale for measuring the weight of the coins/weights.
Feel free to e-mail me if it would be easier than to continue posting the replies.
Thank you!
P.S. I think the carnation trick is a great one! We did this one at home and the kids were wow'ed!! We also have done the salt/pepper separation with oil (or was it dish soap?).
We aren't allowed to email you- we have so many children posting here it is much safer for them if the rules are never give your email out on a forum- never let anyone on the forum try to contact you- etc.
I think the food scale is fine for the salt.
The dead sea is 30-35 % salt. Water weighs 1 g/ mL (notice this is a density-and a very easy one to remember- 1! and the units are grams and mililiters, which is 1/1000 of a liter) . Thankfully, google does unit conversion if you aren't good at them. To find out how many mL are in 8 cups, you can type in the search bar "number of mL per 8 cups" and get:
8 US cup = 1 892.7059 mL
This means you have 1893 mL or 1893 grams of water in your tank (or 67 ounces or about 4 lbs). So, to make a solution that is approximately similar to the dead sea, you would take roughly 1/3 of that (33%)- which is 568 grams. Using google again, we find that it is about 20 ounces, which you could measure in two batches on your scale.
This isn't exactly the correct way to calculate this percent, but it is close. The actual correct way to calculate this value is that the percent salt is the percent of the TOTAL mass (total is the weigh of salt+ water- not just the weight of the water which is what we did above). So the more accurate value is:
33%= (x grams of salt)/(x grams of salt + 1893 grams of water) and solve for x. This gives a salt weight of 848 grams, which is about 30 oz. If you don't follow this, don't worry about it (unless you are very interested, in which case, ask!). I just like to put the more correct answer down as well, in case somebody else needs to know this at a more accurate level.
So, you should be able to put 20-30 oz of salt in your water.
The ocean has a salinity of about 8-9 times less, so I would divide what we calculated above by 8 for the ocean.
I don't know if your family has ever been to Salt Lake City, Utah, but that is named because of one of these hypersaline lakes. For a very long time, this type of lake was a significant source of salt. Either you dried sea water to get salt, or you gathered salt from salt pans/shores of hypersaline lakes. The percentage of salt in the Great Salt Lake in Utah "is highly variable, and depends on the lake's level; it ranges from 5 to 27%" [1] So, if your son has seen this lake, or been to Salt Lake City, this might be a better example than the Dead Sea.
One last bit of math. Water has a density of 1 gm/mL, which is the same as 1 kg/L. So, you can see that even though the Dead Sea has a ton of salt, the density is only 1.17 kg/L. Even though these numbers look very close to each other, it is actually a pretty large change in density which you will see with your experiment.
I think your son will love this project. Not only do you get to play with water, but you get to sink boats too!
Louise
[1] from the wikipedia- you may want to use a "real" encylopedia to double check the numbers. Wikipedia is pretty good on a lot of things, but most teachers like a more permanent reference.