lil bit wrote:The starting weights for the white were:87.1; 86.7;86.15;86.6;86.6.
The starting weights for red were: 89.0; 89.8; 88.3; 87.7; 88.15.
The stareting weights for apple weer: 87.45; 86.4; 86.45; 86.3; 86.7.
I recalculated the standard deviation using the normalization of the starting masses. So, for example, for the white vinegar trial, every thing ideally should weigh 87.1 g. So, the results for the 86.7 trial were 99.5% of what they should be, because the starting weight was only 99.5% of what is should be. (Which is really good- all the standard deviations on these are really fantastic. Obviously you took a lot of care in your measuring.)
The "norm factor" is the percent off the max weight. The "gas" is your experimental value. "norm gas" is the amount of gas you would have measured if you had used a standard weight. Mathematically, I used [(1-norm factor)*gas+ gas). Then I calculated the average and the standard deviation.
white norm factor gas norm gas
87.1 1 1.8 1.8
86.7 0.995407577 1.9 1.908725603
86.15 0.989092997 1.75 1.769087256
86.6 0.994259472 2 2.011481056 ave 1.859925373
86.6 0.994259472 1.8 1.810332951 std 0.099564815
red
89 0.991091314 1.8 1.816035635
89.8 1 1.7 1.7
88.3 0.983296214 1.6 1.626726058
87.7 0.976614699 1.7 1.739755011 ave 1.692199332
88.15 0.981625835 1.55 1.578479955 std 0.093376481
cider
87.45 1 1.75 1.75
86.4 0.987993139 1.7 1.720411664
86.45 0.988564894 1.75 1.770011435
86.3 0.986849628 1.75 1.77301315 ave 1.715345912
86.7 0.991423671 1.55 1.56329331 std 0.087550544
If you look, you see there is overlap between the normalized red and the white vinegar data. That is, 1.8, 1.7, 1.76 could appear in both groups. The standard deviation also says there is some overlap[1]. So, usually, you report the average + and - the standard deviation. So the range of values for the white vinegar based on your trial is 1.86 +/- 0.09, which means that you would believe numbers that were 1.76 to 1.96 (rounded). For red, 1.79 to 1.60 is the range. If you were a scientist, you would do more averages, and more sophisticated statistics to tell if these numbers are different or the same, since it looks "suggestive" that the white vinegar has a higher average value. But, with the data we have, since the ranges do overlap, I'd have to say the results are the same for all vinegars.
Given that this reaction should depend on the amount of acid and baking soda, you might expect that if all are 5% acid, and all are 50 mL, you should get the same result.
Louise
[1] from the wikipedia-
"The standard deviation is the most common measure of statistical dispersion, measuring how widely spread the values in a data set are. If the data points are close to the mean, then the standard deviation is small. Conversely, if many data points are far from the mean, then the standard deviation is large. If all the data values are equal, then the standard deviation is zero."